Question

How do I get the day (1-7) from a Unix timestamp in PHP? I also need the day date (1-31) and month (1-12).

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Solution

You can use date() function

$weekday = date('N', $timestamp); // 1-7
$month = date('m', $timestamp); // 1-12
$day = date('d', $timestamp); // 1-31

OTHER TIPS

see http://docs.php.net/getdate

e.g.

$ts = time(); // could be any timestamp
$d=getdate($ts);

echo 'day of the week: ', $d['wday'], "\n";
echo 'day of the month: ', $d['mday'], "\n";
echo 'month: ', $d['mon'], "\n";

It's the date() function you're after.

You can get more details from the PHP manual but in a nutshell here are the functions you need.

date('N', $timestamp);
//numeric representation of the day of the week

date('j', $timestamp);
//Day of the month without leading zeros

date('n', $timestamp);
//Numeric representation of a month, without leading zeros
print "Week".date('N')."\n";
print "day of month " .date('d')."\n";
print "month ".date('m')."\n";

Use the date function as stated before, with your $timestamp as the second argument:

$weekday = date('N', $timestamp); // 1 = Monday to 7 = Sunday
$month = date('m', $timestamp); // 1-12 = Jan-Dec
$day = date('d', $timestamp); // 1-31, day of the month

Not all PHP versions play nice with negative timestamps. My experience is that timestamps dating back to before the UNIX epoch fare better with the new DateTime object.

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