SQL - Removing Duplicate without 'hard' coding?

Question

Heres my scenario.

I have a table with 3 rows I want to return within a stored procedure, rows are email, name and id. id must = 3 or 4 and email must only be per user as some have multiple entries.

I have a Select statement as follows

SELECT
     DISTINCT email,
     name,
     id
from table
where
     id = 3
     or id = 4

Ok fairly simple but there are some users whose have entries that are both 3 and 4 so they appear twice, if they appear twice I want only those with ids of 4 remaining. I'll give another example below as its hard to explain.

Table -

Email              Name    Id
jimmy@domain.com   jimmy   4
brian@domain.com   brian   4
kevin@domain.com   kevin   3
jimmy@domain.com   jimmy   3

So in the above scenario I would want to ignore the jimmy with the id of 3, any way of doing this without hard coding?

Thanks

Answer 1

SELECT
     email,
     name,
     max(id)
from table
where
     id in( 3, 4 )
group by email, name

Answer 2

Is this what you want to achieve?

SELECT Email, Name, MAX(Id) FROM Table WHERE Id IN (3, 4) GROUP BY Email;

Answer 3

Sometimes using Having Count(*) > 1 may be useful to find duplicated records.

select * from table group by Email having count(*) > 1

or

select * from table group by Email having count(*) > 1 and id > 3.

The solution provided before with the select MAX(ID) from table sounds good for this case. This maybe an alternative solution.

Answer 4

What RDMS are you using? This will return only one "Jimmy", using RANK():

SELECT A.email, A.name,A.id
FROM SO_Table A
INNER JOIN(
SELECT 
email, name,id,RANK() OVER (Partition BY name ORDER BY ID DESC) AS COUNTER
FROM SO_Table B  
) X ON X.ID = A.ID AND X.NAME = A.NAME
WHERE X.COUNTER = 1

Returns:

 email          name    id
 ------------------------------
 jimmy@domain.com   jimmy   4
 brian@domain.com   brian   4
 kevin@domain.com   kevin   3