Floating-point numbers in C

Question

I'm using the following code to get the output up to 5 decimal characters of any number input by user when divided by 1, I have to typecast it with (float).

Can any one tell me how this can be done without typecasting or using float constant?

int main() {
    int n;
    scanf("%d",&n);
    printf("%.5 ", 1/(float)n);
    return 0;
}

Answer 1

You can use this piece of code that uses only integers:

 printf(n==1?"1.00000":"0.%05d ", 100000/n);

Answer 2

Taking your question strictly literally, you could do:

int main() {
    float n;
    scanf("%f",&n);
    printf("%.5f", 1/n);
    return 0;
}

In this code, there is no float literal and no (float) cast.

Answer 3

Technically speaking, this should do it:

printf("%.5f ", 1/pow(n,1));