“request” at the deform validation

Question

i need the "request" for this custom validation in deform to work:

def d_validator(node, value):
    if not value:
        raise Invalid(node, 'Enter a Password')
    if len(value) < 5:
        raise Invalid(node, 'Invalid Length')
    userid = authenticated_userid(userrequest)
    dbsession = DBSession()
    userInfo = dbsession.query(User).filter(_and(User.id==userid, User.password == value)).first()
    if not userInfo:
        raise Invalid(node, 'Invalid password')

so i tried this:

class Form(field.Field):
    def __init__(self, schema, **kw):
        self.saved_user = kw.pop('userrequest')
        log.info(self.saved_user)
        super(Form, self).__init__(schema, **kw)

and then:

Form(schema, buttons=('Actualizar',), 'userrequest'=request)

but i get SyntaxError: keyword can't be an expression

i know this could be python related, bear with me, thanks in advance

Answer 1

Keywords are indeed not expressions, but 'userrequest'=request is. Remove the quotes:

Form(schema, buttons=('Actualizar',), userrequest=request)

Also, why are you basing your custom Form class on field.Field? I haven't used deform yet myself, but from a quick glance at the documentation suggest strongly you should be inheriting from deform.Form instead.

Last but not least, you could fall back to the pyramid thread-local request instead:

def d_validator(node, value):
    if not value:
        raise Invalid(node, 'Enter a Password')
    if len(value) < 5:
        raise Invalid(node, 'Invalid Length')
    userid = authenticated_userid(get_current_request())
    dbsession = DBSession()
    userInfo = dbsession.query(User).filter(_and(User.id==userid, User.password == value)).first()
    if not userInfo:
        raise Invalid(node, 'Invalid password')

Yes, this is often frowned upon, but could be easier in your case to deal with.