How to find texts and replace them using RegEx

Question

Below is an extract from my long text:

As a young researcher, he is required:
\n ÷ to read at least three theses\n ÷ to meet his tutor or supervisor 
once a week\n ÷ to join seminars\n

Now I would like to find any blocks starting with ÷ and ending with \n, and replace ÷ by ÷<font color="blue"> and \n by </font>\n. So, for example, my above extract would appear like this:

As a young researcher, he is required:
\n ÷<font color="blue"> to read at least three theses</font>\n ÷<font color="blue"> 
to meet his tutor or supervisor once a week</font>\n ÷<font color="blue"> to join seminars</font>\n

So far I have been using these Grep in TextWrangler to look for and replace:

(÷[^ \t/<>]*?).*?([^ \t/<>]*?\\n)

<font color="blue">\1\2</font>\3

The required blocks of text are successfully found, but replacing doesn't work as I expect.

I'm using TextWrangler, but may have access to BBEdit or Notepad++.

Can you please help me to solve this problem? Thank you very much.

---

UPDATE

Thanks to DesertEagle, I have worked out the solution. Here is the code:

÷([^\\n]+)\\n
÷<font color="blue">\1</font>\\n

Answer 1

Though I don't have textwrangler at hand, this should work for you [1]

search /÷([^\n]+)\n/

EDIT The correct syntax for textwrangler is ÷([^\\n]+)\\n

replace ÷<font color="blue">\1</font>\n

[1] please ensure proper escaping for your engine