Informix 4GL, how to print?

Question

I have a column (chgkey) with 17 rows of record. How can I print first 3 records in the same line (like, raw1, raw2, raw3). Now I can print the raw1 without any problem. Any help would be appreciated. below is my code.

    let rpt.chgkey =  null
      select * into z_charge.* from charge where charnum in
          (select shtwrd_no from crbookid where
               crbookid.book_no = rpt.book_no and crbookid.line_no = rpt.line_no )

    let scratch = z_charge.chgkey
    let rpt.chgkey = scratch
         call make_charge_section(scratch) returning rpt.chgkey
    print
        column   1, ESC, "(s0p12h0s3b4099T", ESC, "&a0.5R"
    print
    print  ESC,"&a15.1R", ESC,"&a15C", rpt.chgkey

Answer 1

If the SELECT statement (now with INTO clause) returns more than one row, you will get a runtime error unless you wrap it up in a FOREACH loop.

If you have the FOREACH loop inside the REPORT function, then it is fairly easy to deal with; if the data is provided via separate OUTPUT TO REPORT statements, it is harder.

Assuming life is easy, then:

DECLARE c CURSOR FOR
    SELECT * INTO z_charge.*
      FROM charge
     WHERE charnum IN
           (SELECT shtwrd_no FROM crbookid
            WHERE crbookid.book_no = rpt.book_no AND crbookid.line_no = rpt.line_no
           )

LET i = 0
FOREACH c
    PRINT COLUMN (i * 20 + 1), z_charge.raw;
    LET i = i + 1
    IF i MOD 3 = 0 THEN PRINT END IF
END FOREACH
IF i MOD 3 != 0 THEN PRINT END IF

The loop prints the value in z_charge.raw at an appropriate column (you can do calculations on column numbers like that). Of course, this assumes that the raw data fits inside 20 characters.

---

DECLARE c CURSOR FOR
    SQL
    SELECT FIRST 3 * INTO z_charge.*
      FROM charge
     WHERE charnum IN
           (SELECT shtwrd_no FROM crbookid
            WHERE crbookid.book_no = rpt.book_no AND crbookid.line_no = rpt.line_no
           )
    END SQL

Answer 2

Use a semi-colon at the end of the print statement to supress the end of line character.

If you terminate a PRINT statement with a semicolon, however, you suppress the implicit LINEFEED character at the end of the line.

PRINT