Python equivalent of Ruby's expression: “puts x += value”

Question

For curiosity's sake...

In Ruby:

=>$ irb
1.8.7 :001 > puts x = 2
2
 => nil 
1.8.7 :002 > puts x += 2 while x < 40
4
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40

It's quite handy.

Is it possible to do that in Python in a single line and if yes how?

Answer 1

The reason why you can not do exactly or very similarly the same in Python is because in Ruby, everything is expression.

Python distincts between statements and expressions and only expressions can be evaluated (therefore printed, I mean passed to print operator/function).

So such code cannot be done in Python in that form you showed us. Everything you can do is to find some "similar" way to write down statement above as a Python expression but it will definitely not be that "Rubyous".

IMHO, in Python, impossibility of such behaviour (as described in this use case), nicely follows "explicit is better than implicit" Zen of Python rule.

Answer 2

a one-liner to produce the same result:

for x in xrange(4,42,2): print x

gives:

4
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40

xrange is a built in function that returns an “xrange object”, which yields the next item without storing them all (like range does), this is very similar to OP's while loop.

Answer 3

This is not possible in python; you can't use a statement (x += 2) as an expression to be printed.

Answer 4

With the remarks about assigment not being expressions in Python on the other answers kept, one can do this in Python:

from __future__ import print_function

[print(x) for x in range(0,42,2)]