Question

Take the following example code:

with test as (
    select to_date('01/2012', 'mm/yyyy') as dt, '1' as value from dual union all 
    select to_date('02/2012', 'mm/yyyy') as dt, '10' as value from dual union all 
    select to_date('03/2012', 'mm/yyyy') as dt, '100' as value from dual union all 
    select to_date('04/2012', 'mm/yyyy') as dt, '2' as value from dual union all 
    select to_date('05/2012', 'mm/yyyy') as dt, '20' as value from dual 
)
select dt, value from test

which returns:

DT          | VALUE
1/1/2012    | 1
2/1/2012    | 10
3/1/2012    | 100
4/1/2012    | 2
5/1/2012    | 20

I wish I could build a new column containing the previous value of each record, such as:

DT          | VALUE  | Previous
1/1/2012    | 1      | -
2/1/2012    | 10     | 1
3/1/2012    | 100    | 10
4/1/2012    | 2      | 100
5/1/2012    | 20     | 2

Which seems simple enough though I constantly get lost with connect_by statements.

could someone help?

Was it helpful?

Solution

No need to use a CONNECT BY. You just need a LAG

SQL> ed
Wrote file afiedt.buf

  1  with test as (
  2      select to_date('01/2012', 'mm/yyyy') as dt, '1' as value from dual union all
  3      select to_date('02/2012', 'mm/yyyy') as dt, '10' as value from dual union all
  4      select to_date('03/2012', 'mm/yyyy') as dt, '100' as value from dual union all
  5      select to_date('04/2012', 'mm/yyyy') as dt, '2' as value from dual union all
  6      select to_date('05/2012', 'mm/yyyy') as dt, '20' as value from dual
  7  )
  8  select dt,
  9         value,
 10         lag(value) over (order by dt) prior_value
 11*   from test
SQL> /

DT        VAL PRI
--------- --- ---
01-JAN-12 1
01-FEB-12 10  1
01-MAR-12 100 10
01-APR-12 2   100
01-MAY-12 20  2
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