Locate/Find .exe file (javaw.exe) then use elevate.exe and run jar

Question

I tried to make the title as descriptive as possible, but im basically trying to locate javaw.exe because when I launch my JAR cmd only finds java.exe but the prompt window is ugly and I don't want it there.

What works:

java -jar myJar.jar

What I'm trying to do

javaw -jar myJar.jar

What also works:

JAVAWPATH\javaw.exe -jar myJar.jar

I'm trying to make the program adapt to any computer automatically, since I don't know if javaw will always be in the same location.

So I have managed to locate a bunch of "javaw.exe" files using

WHERE /R c:\ *javaw.exe 

I want to select one of the returned paths and set some kind of string variable with which I can then: elevate MYstringPATHtoJAVAW -jar myJar.jar.

Answer 1

I've written a batch script which locates the java instalation folder through the registry:

::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
@ECHO OFF

:: Export java settings from registry to a temporary file
START /W REGEDIT /E %Temp%.\java.reg "HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft"



:: Find java location
FOR /F "tokens=1* delims==" %%A IN ('TYPE %Temp%.\java.reg ^| FIND "INSTALLDIR"') DO SET JAVA_HOME=%%B
SET JAVA_HOME=%JAVA_HOME:"=%
SET JAVA_HOME=%JAVA_HOME:\\=\%
SET JAVA_HOME

:: Get java version
FOR /F "tokens=1* delims==" %%A IN ('TYPE %Temp%.\java.reg ^| FIND "CurrentVersion"') DO SET JAVA_VERSION=%%B
SET JAVA_VERSION=%JAVA_VERSION:"=%
SET JAVA_VERSION
SET JAVA_VERSION=%JAVA_VERSION:.=%
SET JAVA_VERSION=%JAVA_VERSION:_=%
SET /A JAVA_VERSION=%JAVA_VERSION%

:: Delete temp file
@DEL %Temp%.\java.reg /S /Q > NUL 2>&1

:: Check java version compatibility
IF %JAVA_VERSION% LSS 16020 (
ECHO.
ECHO YOU NEED AT LEAST JAVA WITH VERSION 1.6.0_20 -- this is just an example echo.
GOTO :EOF
)

PAUSE
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I've used this as a base.But it might not work properly if the installed java is a 64bit (yes, I must update this script...) , but it can be updated easy.Hope this will help you.