In C#, how to create an object given the name of its type? [duplicate]

Question

This question already has an answer here:

• Create an instance of a class from a string 8 answers

I know the type of object (let's say IAnimal) I need to instantiate, and the name (lets say Tiger). How do I write the code to instantiate Tiger, given that the variable that knows the object name is a string. I'm likely missing something simple here, but am currently stuck on this.

Update: I meant Class Tiger : IAnimal, changed above to reflect that.

Answer 1

Using the Activator.CreateInstance method

example:

// the string name must be fully qualified for GetType to work
string objName = "TestCreateInstance.MyObject";
IProcess txObject = (IProcess)Activator.CreateInstance(Type.GetType(objName));

or

object o = Activator.CreateInstance("Assem1.dll", "Friendly.Greeting");

See also: Reflection Examples C#

Answer 2

Use reflection to instantiate an object of a class by its type name.

object o = Activator.CreateInstance(Type.GetType("Tiger"));

Note that you cannot instantiate interfaces (judging by your naming), as they are merely a contract that defines what a specific class should implement.

Answer 3

I am not sure I fully understand the question. However, assuming that ITiger is actually a concrete class and not an interface (as the I* would suggest).

You can use reflection to create and instance of a type from a string.

Something like:

ITiger myTiger = Activator.CreateInstance("ITiger") as ITiger;

http://msdn.microsoft.com/en-us/library/system.activator.createinstance.aspx

Is that what you are asking?