Imagine you have a messaage queue with the following API
class MQ {
public MQ();
// send a single message from your message queue
public void send(string keyPath, string msg);
// Receive a single message from your message queue
public async Task<string> receive(keyPath);
}
To make this RX compatible
class MQRX: IObserver<string> {
MQ _mq;
string _keyPath
MQRX(string keyPath){
_mq = mq;
_keyPath = keyPath;
}
IObservable<string> Observe(){
return Observable.Defer(()=> mq.receive(keyPath).ToObservable() ).Repeat();
}
void OnNext(string msg){
_mq.send(msg);
}
void OnError(Exception e){
// The message queue might not
// support serializing exceptions
// or it might or you might build
// a protocol for it.
}
}
To use it in a fault tolerant way. Note Retry will resubscribe if there is an exception thrown upstream delivered by OnError
new MQRX("users/1/article/2").
Retry().
Subscribe((msg)=>Console.Writeln(msg));
On the writing side for example you could send a message every two seconds and retry the subscription to the generator if there is an error. Note there is unlikely to be an error in Observable.Interval that just generates a message every time interval but imagine reading from a file or some other message queue.
var mq = new MQRX("users/1/article/2");
Observable.Interval(TimeSpan.FromSeconds(2)).
Select((x)=>x.ToString()).
Note you probably should use the IObservable Catch extension method rather than blindly retrying as you might get the same error over and over again. Retry(). Subscribe(mq);