Smarty substr string skip first characters

Question

The variable $siteroot contains a string that looks like:

http://www.example.nl/folder/

To get the part http://www.example.nl/ you use:

{$siteroot|substr:0:22}

But i want to skip this part and return /folder/

The length of the folder is unknown.

Answer 1

{$siteroot|substr:22}

Should work

Answer 2

{assign var="bar_at" value=$siteroot|strpos:"nl/"}
{$siteroot|substr:$bar_at+2}