Question

Is there a way to create a condition like this?

@products = Product.find(:all,
  :limit => 5,
  :conditions => { :products => { :locale => 'en', :id NOT '1' }, :tags => { :name => ['a','b']})

I would like to list all products not including product 1. Thx.

Was it helpful?

Solution

Rails 3

Use squeel gem.

Product.where(
  :products => { :locale => 'en', :id.not_in => '1' }, 
  :tags => { :name => ['a','b']}
).limit(5)

Rails 2

Use AR Extensions for this. It supports the following condition modifiers:

* _lt => less than
* _gt => greater than
* _lte => less than or equal to
* _gte => greater than or equal to
* _ne => not equal to
* _not => not equal to

Now you can rewrite your query as follows:

@products = Product.find(:all,
  :limit => 5,
  :joins => [:tags],
  :conditions => { :locale => 'en', :id_not => '1', :tags => { :name => ['a','b']}
)

OTHER TIPS

It should be something like this. The original query wasn't really clear, adapt it to your needs.

@products = Product.find(:all,
  :limit => 5,
  :conditions => ["locale = ? AND id <> ? AND tags.name IN (?)", "en", 1, ['a','b'],
  :joins => "tags"
)

Another way is to use the merge_conditions which turns the hash conditions into a string. Then you can add on whatever you want or call merge_conditions again with other options.

hash_conditions = {:category => 'computers'}
conditions = Product.merge_conditions(hash_conditions) + ' AND products.id NOT IN(1139) '
products = Product.find(:all, :conditions => conditions)

Rails 3.2.9


Controller

  @products = Product.english_but_not(1).with_tags('a','b').limit(5)

Model

class Product < ActiveRecord::Base
  attr_accessible :locale
  has_many :tags
  scope :english, -> { where(:locale => 'en') }
  scope :except_id, ->(id) { where(arel_table[:id].not_eq(id)) }
  scope :english_but_not, ->(id) { english.except_id(id) }
  scope :with_tags, ->(*names) { includes(:tags).where(:tags => {:name => names}) }
end
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