How to know if an object has an attribute in Python

Question

Is there a way in Python to determine if an object has some attribute? For example:

>>> a = SomeClass()
>>> a.someProperty = value
>>> a.property
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: SomeClass instance has no attribute 'property'

How can you tell if a has the attribute property before using it?

Answer 1

Try hasattr():

if hasattr(a, 'property'):
    a.property

EDIT: See zweiterlinde's answer below, who offers good advice about asking forgiveness! A very pythonic approach!

The general practice in python is that, if the property is likely to be there most of the time, simply call it and either let the exception propagate, or trap it with a try/except block. This will likely be faster than hasattr. If the property is likely to not be there most of the time, or you're not sure, using hasattr will probably be faster than repeatedly falling into an exception block.

Answer 2

As Jarret Hardie answered, hasattr will do the trick. I would like to add, though, that many in the Python community recommend a strategy of "easier to ask for forgiveness than permission" (EAFP) rather than "look before you leap" (LBYL). See these references:

EAFP vs LBYL (was Re: A little disappointed so far)
EAFP vs. LBYL @Code Like a Pythonista: Idiomatic Python

ie:

try:
    doStuff(a.property)
except AttributeError:
    otherStuff()

... is preferred to:

if hasattr(a, 'property'):
    doStuff(a.property)
else:
    otherStuff()

Answer 3

You can use hasattr() or catch AttributeError, but if you really just want the value of the attribute with a default if it isn't there, the best option is just to use getattr():

getattr(a, 'property', 'default value')

Answer 4

I think what you are looking for is hasattr. However, I'd recommend something like this if you want to detect python properties-

try:
    getattr(someObject, 'someProperty')         
except AttributeError:
    print "Doesn't exist"
else
    print "Exists"

The disadvantage here is that attribute errors in the properties __get__ code are also caught.

Otherwise, do-

if hasattr(someObject, 'someProp'):
    #Access someProp/ set someProp
    pass

Docs:http://docs.python.org/library/functions.html
Warning:
The reason for my recommendation is that hasattr doesn't detect properties.
Link:http://mail.python.org/pipermail/python-dev/2005-December/058498.html

Answer 5

According to pydoc, hasattr(obj, prop) simply calls getattr(obj, prop) and catches exceptions. So, it is just as valid to wrap the attribute access with a try statement and catch AttributeError as it is to use hasattr() beforehand.

a = SomeClass()
try:
    return a.fake_prop
except AttributeError:
    return default_value

Answer 6

I would like to suggest avoid this:

try:
    doStuff(a.property)
except AttributeError:
    otherStuff()

The user @jpalecek mentioned it: If an AttributeError occurs inside doStuff(), you are lost.

Maybe this approach is better:

try:
    val = a.property
except AttributeError:
    otherStuff()
else:
    doStuff(val)

Answer 7

Depending on the situation you can check with isinstance what kind of object you have, and then use the corresponding attributes. With the introduction of abstract base classes in Python 2.6/3.0 this approach has also become much more powerful (basically ABCs allow for a more sophisticated way of duck typing).

One situation were this is useful would be if two different objects have an attribute with the same name, but with different meaning. Using only hasattr might then lead to strange errors.

One nice example is the distinction between iterators and iterables (see this question). The __iter__ methods in an iterator and an iterable have the same name but are semantically quite different! So hasattr is useless, but isinstance together with ABC's provides a clean solution.

However, I agree that in most situations the hasattr approach (described in other answers) is the most appropriate solution.

Answer 8

Hope you expecting hasattr(), but try to avoid hasattr() and please prefer getattr(). getattr() is faster than hasattr()

using hasattr():

 if hasattr(a, 'property'):
     print a.property

same here i am using getattr to get property if there is no property it return none

   property = getattr(a,"property",None)
    if property:
        print property

Answer 9

EDIT:This approach has serious limitation. It should work if the object is an iterable one. Please check the comments below.

If you are using Python 3.6 or higher like me there is a convenient alternative to check whether an object has a particular attribute:

if 'attr1' in obj1:
    print("attr1 = {}".format(obj1["attr1"]))

However, I'm not sure which is the best approach right now. using hasattr(), using getattr() or using in. Comments are welcome.

Answer 10

Here's a very intuitive approach :

if 'property' in dir(a):
    a.property

Answer 11

You can check whether object contains attribute by using hasattr builtin method.

For an instance if your object is a and you want to check for attribute stuff

>>> class a:
...     stuff = "something"
... 
>>> hasattr(a,'stuff')
True
>>> hasattr(a,'other_stuff')
False

The method signature itself is hasattr(object, name) -> bool which mean if object has attribute which is passed to second argument in hasattr than it gives boolean True or False according to the presence of name attribute in object.

Answer 12

This is super simple, just use dir(object)
This will return a list of every available function and attribute of the object.