Making urls.py file for Flask like in Django

Question

Maybe someone can help/explain me, how to create urls.py file for Flask like in Django?

• main.py - main project file. It includes only app runner (app.run()).
• urls.py is situated in the same directory and need to provide views from views.py.

Answer 1

You can do this as is described in the Flask documentation, basically by calling app.add_url_rule to set your routes rather than using the decorator.

Answer 2

In addition to the Flask documentation, this can be solved like this:

When creating the Flask app load your 'urls.py' file

app.register_blueprint(apps.someapp.urls.mod)

Then structure urls.py as following:

from flask import Blueprint
from apps.someapp.views import SomeView

# set method as endpoint
view = SomeView.as_view('someview')

# Create the blueprint for this app
mod = Blueprint("payment_methods", __name__, url_prefix="/someapp/", template_folder="templates")

# Add the view as route; methods like GET, POST, PUT will automatically route to class methods with parameters
mod.add_url_rule('<int:id>/', view_func=view)