How to fetch the most recent timestamped record for the same id from MySQL table? [duplicate]

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Closed 9 years ago.

Possible Duplicate:
Fetch the row which has the Max value for a column

I have an audit table of people and the number of shares they own at a particular timestamp. How do I fetch the most recent record for a given id?

mysql audit table

id name shares  dateadded 
1  Abc  12      2012-10-06 12:18:21
2  Klm  23      2012-10-06 12:18:21
3  Jim  45      2012-10-06 12:18:21
1  Abc  35      2012-11-06 12:18:21
1  Abc  65      2012-11-17 12:18:21
2  Klm  13      2012-11-06 12:18:21

My desired output :

id name shares  dateadded 
1  Abc  65      2012-11-17 12:18:21
2  Klm  13      2012-11-06 12:18:21
3  Jim  45      2012-10-06 12:18:21

I could do something like this :

select a.* from audittable a join audittable b 
on a.id = b.id
where a.dateadded > b.dateadded;

But that gives me only those most recent records that are repeating. In this case ids 1,2 and not 3. How to get a list of most recent records for all IDs without sub-queries or temp tables?

Answer 1

You will need a subquery, however not subselects (which have a very negative performance hit).

JOIN against a subquery which returns the id and MAX(dateadded) aggregate. The subquery join is needed to be able to match all the other column values in the row containing the latest timestamp.

SELECT
  audittable.id,
  name,
  shares,
  audittable.dateadded
FROM
  audittable
  /* Subquery returns id dateadded grouped by id */
  JOIN (
    SELECT id, MAX(dateadded) AS dateadded FROM audittable GROUP BY id
    /* JOIN condition is on both id and dateadded between the two tables */
  ) maxtimestamp ON audittable.id = maxtimestamp.id AND audittable.dateadded = maxtimestamp.dateadded

Here is a demonstration on SQLfiddle

Answer 2

Without subqueries, you are limited to this

SELECT id, MAX(dateAdded)
FROM audittable
GROUP BY id

If you want the other columns, you need a subquery like Michael Berkowski's answer