I cannot calculate a division in my SQL code

Question

The following code works without problems:

select donem, mekankodu, count(yayin_kodu) yc, 
       SUM(CASE WHEN iade =0 THEN 1 ELSE 0 END) yys
from 
(    select donem,
            bayi_adi,
            bayi_kodu,
            x.mekankodu,
            mekan_adi,
            mekan_tipi,
            yayin_kodu,
            yayin_adi,
            sum(x.b2b_dagitim + x.b2b_transfer) sevk,
            sum(x.b2b_iade) iade,
            sum(x.b2b_dagitim + x.b2b_transfer - x.b2b_iade) satis
    from mps_view2 x
    where x.donem = '200910'
    and x.yayin_kodu in (93,95,98,99,103,174,307,309,311,489,491,495,533,534,538,605,641,642,650,2539,
                         2697,4560,5049,5772,5950,5980,7318,7440,8086,8524,11161,12707,12708,12709,14376,
                         15107,15309,15633)
    and x.mekankodu in (31851,38569,7123,7403,7481)
    group by donem, bayi_adi, bayi_kodu, mekankodu, mekan_adi, mekan_tipi, yayin_kodu, yayin_adi
    order by donem, bayi_kodu, mekan_adi, yayin_adi
)
group by donem, mekankodu

When I want to include yc/yss in my result table, I arrange the SELECT part as follows:

select donem, mekankodu, count(yayin_kodu) yc, 
       SUM(CASE WHEN iade =0 THEN 1 ELSE 0 END) yys,
       yc/yys yo

but it gives

ORA-00904 Error: YYS: Invalid identifier.

What should I do?

Answer 1

Use a with statement:

with subquery_name as
(
    select
       donem,
       mekankodu,
       count(yayin_kodu) as yc, 
       SUM(CASE WHEN iade =0 THEN 1 ELSE 0 END) as yys
    from
        ...
)
select
    donem,
    mekankodu,
    yc,
    yys,
    yc/yys as yo
from
    subquery_name

This is a very useful feature of PL/SQL. You're trying to access a generated column within the same query, which is not possible. A with statement will allow you to calculate a new column based on another calculated column as you are doing here.

Answer 2

You cannot refer to other columns in the same select. Use a sub-select:

select donem, mekankodu, yc, yys, yc/yys yo
from
(
    select donem, mekankodu, count(yayin_kodu) yc,
        SUM(CASE WHEN iade =0 THEN 1 ELSE 0 END) yys,
        yc/yys yo
    from ...
) Sub

Answer 3

You can't access a neighborly-created column in SQL, you can however access the data directory:

select donem, mekankodu, count(yayin_kodu) yc, 
       SUM(CASE WHEN iade =0 THEN 1 ELSE 0 END) yys,
       count(yayin_kodu)/SUM(CASE WHEN iade =0 THEN 1 ELSE 0 END) "yc/yys"
from 
(    select donem,
            bayi_adi,
            bayi_kodu,
            x.mekankodu,
            mekan_adi,
            mekan_tipi,
            yayin_kodu,
            yayin_adi,
            sum(x.b2b_dagitim + x.b2b_transfer) sevk,
            sum(x.b2b_iade) iade,
            sum(x.b2b_dagitim + x.b2b_transfer - x.b2b_iade) satis
    from mps_view2 x
    where x.donem = '200910'
    and x.yayin_kodu in (93,95,98,99,103,174,307,309,311,489,491,495,533,534,538,605,641,642,650,2539,
                         2697,4560,5049,5772,5950,5980,7318,7440,8086,8524,11161,12707,12708,12709,14376,
                         15107,15309,15633)
    and x.mekankodu in (31851,38569,7123,7403,7481)
    group by donem, bayi_adi, bayi_kodu, mekankodu, mekan_adi, mekan_tipi, yayin_kodu, yayin_adi
    order by donem, bayi_kodu, mekan_adi, yayin_adi
)
group by donem, mekankodu

Note: This isn't inefficient like it looks...SQL is smart enough to do the calculation once and use the result twice in most cases. More often than not, trust the optimizer.

Answer 4

Did you forget "as"?

select donem, mekankodu, count(yayin_kodu) yc, 
   SUM(CASE WHEN iade =0 THEN 1 ELSE 0 END) AS yys