Question

Lets suppose that I have some pages

  • some.web/articles/details/5
  • some.web/users/info/bob
  • some.web/foo/bar/7

that can call a common utility controller like

locale/change/es or authorization/login

How do I get these methods (change, login) to redirect to the previous actions (details, info, bar) while passing the previous parameters to them (5, bob, 7)?

In short: How do I redirect to the page that I just visited after performing an action in another controller?

Was it helpful?

Solution

try:

public ActionResult MyNextAction()
{
    return Redirect(Request.UrlReferrer.ToString());
}

alternatively, touching on what darin said, try this:

public ActionResult MyFirstAction()
{
    return RedirectToAction("MyNextAction",
        new { r = Request.Url.ToString() });
}

then:

public ActionResult MyNextAction()
{
    return Redirect(Request.QueryString["r"]);
}

OTHER TIPS

If you want to redirect from a button in the View you could use:

@Html.ActionLink("Back to previous page", null, null, null, new { href = Request.UrlReferrer})

If you are not concerned with unit testing then you can simply write:

return Redirect(ControllerContext.HttpContext.Request.UrlReferrer.ToString());

A suggestion for how to do this such that:

  1. the return url survives a form's POST request (and any failed validations)
  2. the return url is determined from the initial referral url
  3. without using TempData[] or other server-side state
  4. handles direct navigation to the action (by providing a default redirect)

.

public ActionResult Create(string returnUrl)
{
    // If no return url supplied, use referrer url.
    // Protect against endless loop by checking for empty referrer.
    if (String.IsNullOrEmpty(returnUrl)
        && Request.UrlReferrer != null
        && Request.UrlReferrer.ToString().Length > 0)
    {
        return RedirectToAction("Create",
            new { returnUrl = Request.UrlReferrer.ToString() });
    }

    // Do stuff...
    MyEntity entity = GetNewEntity();

    return View(entity);
}

[AcceptVerbs(HttpVerbs.Post)]
public ActionResult Create(MyEntity entity, string returnUrl)
{
    try
    {
        // TODO: add create logic here

        // If redirect supplied, then do it, otherwise use a default
        if (!String.IsNullOrEmpty(returnUrl))
            return Redirect(returnUrl);
        else
            return RedirectToAction("Index");
    }
    catch
    {
        return View();  // Reshow this view, with errors
    }
}

You could use the redirect within the view like this:

<% if (!String.IsNullOrEmpty(Request.QueryString["returnUrl"])) %>
<% { %>
    <a href="<%= Request.QueryString["returnUrl"] %>">Return</a>
<% } %>

In Mvc using plain html in View Page with java script onclick

<input type="button" value="GO BACK" class="btn btn-primary" 
onclick="location.href='@Request.UrlReferrer'" />

This works great. hope helps someone.

@JuanPieterse has already answered using @Html.ActionLink so if possible someone can comment or answer using @Url.Action

Pass a returnUrl parameter (url encoded) to the change and login actions and inside redirect to this given returnUrl. Your login action might look something like this:

public ActionResult Login(string returnUrl) 
{
    // Do something...
    return Redirect(returnUrl);
}

I'm using .Net Core 2 MVC , and this one worked for me, in the controller use HttpContext.Request.Headers["Referer"];

You could return to the previous page by using ViewBag.ReturnUrl property.

To dynamically construct the returnUrl in any View, try this:

@{
    var formCollection =
        new FormCollection
            {
                new FormCollection(Request.Form),
                new FormCollection(Request.QueryString)
            };

    var parameters = new RouteValueDictionary();

    formCollection.AllKeys
        .Select(k => new KeyValuePair<string, string>(k, formCollection[k])).ToList()
        .ForEach(p => parameters.Add(p.Key, p.Value));
}

<!-- Option #1 -->
@Html.ActionLink("Option #1", "Action", "Controller", parameters, null)

<!-- Option #2 -->
<a href="/Controller/Action/@object.ID?returnUrl=@Url.Action(ViewContext.RouteData.Values["action"].ToString(), ViewContext.RouteData.Values["controller"].ToString(), parameters)">Option #2</a>

<!-- Option #3 -->
<a href="@Url.Action("Action", "Controller", new { object.ID, returnUrl = Url.Action(ViewContext.RouteData.Values["action"].ToString(), ViewContext.RouteData.Values["controller"].ToString(), parameters) }, null)">Option #3</a>

This also works in Layout Pages, Partial Views and Html Helpers

Related: MVC3 Dynamic Return URL (Same but from within any Controller/Action)

Licensed under: CC-BY-SA with attribution
Not affiliated with StackOverflow
scroll top