How to start a program and exit immediately using apache commons-exec?

Question

By using Apache Commons-Exec I can start a program successfully, however the starter program suspended after the program started.

May I ask how to start a program and exit immediately so it will not block the following execution?

DefaultExecutor executor = new DefaultExecutor();
executor.execute( "cmd /c start C:\\Users\\xx\\program.exe");

I'm on Win7 64bit.

Thanks

Answer 1

According to documentation, execute(CommandLine) starts synchronous execution. That is, it blocks the calling thread. You probably want asynchronous execution, so use execute(CommandLine command, ExecuteResultHandler handler). For example,

DefaultExecutor executor = new DefaultExecutor();
executor.execute(new CommadLine("cmd /c start C:\\Users\\xx\\program.exe"),
                 new DefaultExecuteResultHandler());

Answer 2

Sounds like you need to use a DefaultExecuteResultHandler.

See the tutorial (bottom of) for more info.