How can I get the name of function inside a JavaScript function?
-
23-09-2019 - |
Question
How is it possible to learn the name of function I am in?
The below code alerts 'Object'. But I need to know how to alert "Outer."
function Outer(){
alert(typeof this);
}
Solution
I think that you can do that :
var name = arguments.callee.toString();
For more information on this, take a look at this article.
function callTaker(a,b,c,d,e){
// arguments properties
console.log(arguments);
console.log(arguments.length);
console.log(arguments.callee);
console.log(arguments[1]);
// Function properties
console.log(callTaker.length);
console.log(callTaker.caller);
console.log(arguments.callee.caller);
console.log(arguments.callee.caller.caller);
console.log(callTaker.name);
console.log(callTaker.constructor);
}
function callMaker(){
callTaker("foo","bar",this,document);
}
function init(){
callMaker();
}
OTHER TIPS
This will work:
function test() {
var z = arguments.callee.name;
console.log(z);
}
As of ES6, you can use Function.prototype.name
. This has the added benefit of working with arrow functions, since they do not have their own arguments object.
function logFuncName() {
console.log(logFuncName.name);
}
const logFuncName2 = () => {
console.log(logFuncName2.name);
};
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