If you limit yourself to words combined from two other words, you can check the combinations yourself:
>>> s = "applebanana"
>>> splits = [(s[:i], s[i:]) for i in range(1,len(s))]
>>> splits
[('a', 'pplebanana'), ('ap', 'plebanana'), ('app', 'lebanana'),
('appl', 'ebanana'), ('apple', 'banana'), ('appleb', 'anana'),
('appleba', 'nana'), ('appleban', 'ana'), ('applebana', 'na'),
('applebanan', 'a')]
>>> any((eng.check(item[0]) and eng.check(item[1])) for item in splits)
True
Of course you can expand that to more than two, but this should give you a general idea of where you're headed.