How do I print Python 2.5 Exception arguments?

Question

Does python 2.5 allow you to pass exception arguments?

try: raise Exception("argument here")
except Exception: print Exception.args

I've had no luck with the above code - I know this is how you do it in Python 2.7 - is this not in Python 2.5?

Answer 1

You aren't actually raising the exception, just creating it. Once you fix that, you also need to refer to the instance that gets raised, not just the Exception class:

>>> try: 
...     raise Exception('foo', 23)
... except Exception, e: 
...     print e.args
... 
('foo', 23)