Question

I need to check if value is defined as anything, including null. isset treats null values as undefined and returns false. Take the following as an example:

$foo = null;

if(isset($foo)) // returns false
if(isset($bar)) // returns false
if(isset($foo) || is_null($foo)) // returns true
if(isset($bar) || is_null($bar)) // returns true, raises a notice

Note that $bar is undefined.

I need to find a condition that satisfies the following:

if(something($bar)) // returns false;
if(something($foo)) // returns true;

Any ideas?

Was it helpful?

Solution

IIRC, you can use get_defined_vars() for this:

$foo = NULL;
$vars = get_defined_vars();
if (array_key_exists('bar', $vars)) {}; // Should evaluate to FALSE
if (array_key_exists('foo', $vars)) {}; // Should evaluate to TRUE

OTHER TIPS

If you are dealing with object properties whcih might have a value of NULL you can use: property_exists() instead of isset()

<?php

class myClass {
    public $mine;
    private $xpto;
    static protected $test;

    function test() {
        var_dump(property_exists($this, 'xpto')); //true
    }
}

var_dump(property_exists('myClass', 'mine'));   //true
var_dump(property_exists(new myClass, 'mine')); //true
var_dump(property_exists('myClass', 'xpto'));   //true, as of PHP 5.3.0
var_dump(property_exists('myClass', 'bar'));    //false
var_dump(property_exists('myClass', 'test'));   //true, as of PHP 5.3.0
myClass::test();

?>

As opposed with isset(), property_exists() returns TRUE even if the property has the value NULL.

See Best way to test for a variable's existence in PHP; isset() is clearly broken

 if( array_key_exists('foo', $GLOBALS) && is_null($foo)) // true & true => true
 if( array_key_exists('bar', $GLOBALS) && is_null($bar)) // false &  => false

I have found that compact is a function that ignores unset variables but does act on ones set to null, so when you have a large local symbol table I would imagine you can get a more efficient solution over checking array_key_exists('foo', get_defined_vars()) by using array_key_exists('foo', compact('foo')):

$foo = null;
echo isset($foo) ? 'true' : 'false'; // false
echo array_key_exists('foo', compact('foo')) ? 'true' : 'false'; // true
echo isset($bar) ? 'true' : 'false'; // false
echo array_key_exists('bar', compact('bar')) ? 'true' : 'false'; // false

Update

As of PHP 7.3 compact() will give a notice for unset values, so unfortunately this alternative is no longer valid.

compact() now issues an E_NOTICE level error if a given string refers to an unset variable. Formerly, such strings have been silently skipped.

The following code written as PHP extension is equivalent to array_key_exists($name, get_defined_vars()) (thanks to Henrik and Hannes).

// get_defined_vars()
// https://github.com/php/php-src/blob/master/Zend/zend_builtin_functions.c#L1777
// array_key_exists
// https://github.com/php/php-src/blob/master/ext/standard/array.c#L4393

PHP_FUNCTION(is_defined_var)
{

    char *name;
    int name_len;

    if (zend_parse_parameters(ZEND_NUM_ARGS() TSRMLS_CC, "s", &name, &name_len) == FAILURE) {
        return;
    }

    if (!EG(active_symbol_table)) {
        zend_rebuild_symbol_table(TSRMLS_C);
    }

    if (zend_symtable_exists(EG(active_symbol_table), name, name_len + 1)) {
        RETURN_TRUE;
    }

}

You could use is_null and empty instead of isset(). Empty doesn't print an error message if the variable doesn't exist.

Here some silly workaround using xdebug. ;-)

function is_declared($name) {
    ob_start();
    xdebug_debug_zval($name);
    $content = ob_get_clean();

    return !empty($content);
}

$foo = null;
var_dump(is_declared('foo')); // -> true

$bla = 'bla';
var_dump(is_declared('bla')); // -> true

var_dump(is_declared('bar')); // -> false

is_null($bar) returns true, since it has no values at all. Alternatively, you can use:

if(isset($bar) && is_null($bar)) // returns false

to check if $bar is defined and will only return true if:

$bar = null;
if(isset($bar) && is_null($bar)) // returns true
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