Python ftplib file open() TypeError

Question

I am trying to upload a file to an ftp server with python using the ftplib.

This is what i have:

def ftp(cmd):

    cmd = cmd.split(' ')
    try: cmd[3]
    except: return 'host user password file (ftpdir)'
    try: session = ftplib.FTP(cmd[0],cmd[1],cmd[2])
    except: return 'wrong credentials/host'
    try: file = open(cmd[3], 'rb')
    except: return 'unable to reach file'
    try: cmd[4]
    except: pass
    else: 
        if cmd[4] !='':
            ftplib.FTP.cwd(ftpdir)
    name = file.split('\\')[-1]
    session.storbinary('STOR ' + name, file)     # send the file
    file.close()                                    # close file and FTP
    session.quit()

I give the function a command in the form of 'host user password file ftpdir' where ftpdir is not required. The error I get is this one:

Traceback (most recent call last):

  ...some lines of referring...

  File "C:\somedir\somefile.py", line 155, in ftp
    file = open(cmd[3],'rb')
TypeError: open() takes exactly 1 argument (2 given)

If i try the command "file = open(cmd[3], 'rb')" with a given 'cmd' as entry in a python shell it works fine.

Answer 1

This question is now answered. The problem was that I defined another function open(arg) which took exactely one argument. After changing the name of that function, everything worked fine.

Thank you for your time everyone who read this.