Question

I'm attempting something like the following:

struct MyType { };

template <typename T>
struct Test
{
    static const MyType * const sm_object;
};

template <>
struct Test<void>
{
    static const MyType * const sm_object;
};

template <typename T> const MyType * const Test<T>::sm_object = new MyType();
template <> const MyType * const Test<void>::sm_object = new MyType();

I include this in 2 files - a.cpp and b.cpp. I attempt to compile and get:

error C2998: 'const MyType *Test<void>::sm_object' : cannot be a template definition

I assume my C++ syntax is bad, but I can't think what I'm doing wrong.

I can't remove the template<> from the variable definition, as I need this in multiple translation units, and that would result in a link error.

I could put the field into a base class and use the CRTP to create a new instance per type, and then the specialization wouldn't get in the way, but why doesn't this 'direct' field initialisation work? I must be missing some piece of syntax.

I'm using VS2003 :(

Was it helpful?

Solution

Judging from g++ I think you need to remove the template<> from that line and put the remainder in just one source file (not in the header). Since it's a specialization it's just like a normal non-template static which you don't define in a header.

In some .C file:

const MyType * const Test<void>::sm_object = new MyType();

OTHER TIPS

I believe that you want to do something like this

struct MyType { };

template <typename T>
struct Test
{
    static const MyType * const sm_object;
    static const MyType* set_object()
    {
        return nullptr;
    }
};

template <>
struct Test<void>
{
    static const MyType * const sm_object;
    static const MyType* set_object()
    {
        return new MyType();
    }
};

template <typename T> 
const MyType * Test<T>::sm_object = Test< T >::set_object();

I believe the following code could be of quite some interest for some people:

#include <stdio.h>
template<class X,int Y>
struct B
{
  X content;
  static const int nr=Y;
};

int main(int, char**)
{
  B<char,1> a;
  B<int,2> b;
  B<int,3> c;
  printf("%d, %d, %d\n",a.nr,b.nr,c.nr);
}
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