Question

I am currently using SQL Server 2008, and I am trying to create a statement using a table variable to insert multiple rows into the table. As it stands right now, I have to insert the information being added in 4 different spots(2 select statements, 1 insert and 1 update), but would like to be able to create a single table variable, so I only have to enter the information once. Any help/suggestions would be greatly appreciated.

This is an example of what I am trying to change.

PRINT 'Before'
SELECT  GROUPID, ModifiedBy, ModifiedDate
FROM TableXYZ
WHERE groupID in(ID1, ID2, ID3, ID4)                                                            

BEGIN TRAN


Insert into TableXYZ
 (GROUPID)
VALUES
 (ID1), (ID2), (ID3), (ID4)                                                             



UPDATE TableXYZ
SET existingdays = 15
    ,ModifiedBy = @userID
    ,ModifiedDate = @today
WHERE groupID in(ID1, ID2, ID3, ID4)                                                            


Set  @RowCount =  @@ROWCOUNT 


PRINT 'After '

SELECT  GROUPID, ModifiedBy, ModifiedDate
FROM TableXYZ
WHERE groupID in(ID1, ID2, ID3, ID4)    
Was it helpful?

Solution

Is this what you are looking for in terms of only entering the information once?

DECLARE @IDList TABLE
(
    ID INT
)

INSERT INTO @IDList ( ID )
VALUES
     (ID1)
    ,(ID2)
    ,(ID3)
    ,(ID4)

PRINT 'Before'
SELECT  GROUPID, ModifiedBy, ModifiedDate
FROM TableXYZ AS T
    INNER JOIN @IDList AS L
        ON T.GroupID = L.ID

BEGIN TRAN


Insert into TableXYZ
 (GROUPID)
SELECT ID
FROM @IDList


UPDATE TableXYZ
SET existingdays = 15
    ,ModifiedBy = @userID
    ,ModifiedDate = @today
FROM TableXYZ AS T
    INNER JOIN @IDList AS L
        ON T.GroupID = L.ID


Set  @RowCount =  @@ROWCOUNT 


PRINT 'After '

SELECT  GROUPID, ModifiedBy, ModifiedDate
FROM TableXYZ AS T
    INNER JOIN @IDList AS L
        ON T.GroupID = L.ID

OTHER TIPS

To insert into table1 values from table2:

INSERT INTO table1 ( column1 )
SELECT  col1
FROM    table2
Licensed under: CC-BY-SA with attribution
Not affiliated with StackOverflow
scroll top