groovy: how to replaceAll ')' with ' '
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26-09-2019 - |
Question
I tried this:
def str1="good stuff 1)"
def str2 = str1.replaceAll('\)',' ')
but i got the following error:
Exception org.codehaus.groovy.control.MultipleCompilationErrorsException: startup failed, Script11.groovy: 3: unexpected char: '\' @ line 3, column 29. 1 error at org.codehaus.groovy.control.ErrorCollector(failIfErrors:296)
so the question is how do I do this:
str1.replaceAll('\)',' ')
Solution
Same as in Java:
def str2 = str1.replaceAll('\\)',' ')
You have to escape the backslash (with another backslash).
OTHER TIPS
A more Groovy way: def str2 = str1.replaceAll(/\)/,' ')
You have to escape the \
inside the replaceAll
def str2 = str1.replaceAll('\\)',' ')
The other answers are correct for this specific example; however, in real cases, for instance when parsing a result using JsonSlurper
or XmlSlurper
and then replacing a character in it, the following Exception occurs:
groovy.lang.MissingMethodException: No signature of method: java.util.ArrayList.replaceAll() is applicable for argument types
Consider the following example,
def result = new JsonSlurper().parseText(totalAddress.toURL().text)
If one wants to replace a character such as '('
in result
with a ' '
for example, the following returns the above Exception
:
def subResult = result.replaceAll('\\(',' ')
This is due to the fact that the replaceAll
method from Java works only for string
types. For this to work, toString()
should be added to the result of a variable defined using def
:
def subResult = result.toString().replaceAll('\\[',' ')