What's the opposite of JavaScript's Math.pow?
-
26-09-2019 - |
Question
I'm having a mental block here, and algebra not really being my thing, can you tell me how to re-write the JavaScript code below to derive the variable, c
, in terms of a
and b
?:
a = Math.pow(b, c);
c = ?
Thanks!
Solution
c = Math.log(a)/Math.log(b)
OTHER TIPS
Logarithms. You want the logarithm of a. B is the base, c is the exponent, so
logb a = c
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