Mongoid, help with notifications

Question

I've got notification embedded in user. In Mongoid, how would I achieve a similar query. The query below is done using Mongdb:

MONGODB site_name_development['users'].update(
  {"_id"=>BSON::ObjectId('4ce694e672357e015a000014'), 
  "notifications._id"=>BSON::ObjectId('4ce694e672357e015a000017')}, 
{"$set"=>{"notifications.0.is_active"=>true}})

Basically, if I have user Foobar. Foobar has 3 types of notifications. I'd like to turn one of this notifications on by setting is_active to true. At the same time all other notification's is_active should be set to false

What query should be executed?

Answer 1

The equivalent code would be something like this:

notification = User.find('4ce694e672357e015a000014').notifications.find('4ce694e672357e015a000017').update_attributes!(:active => true)

If you then wanted to set the others to inactive:

User.find('4ce694e672357e015a000014').notifications.excludes(:id => '4ce694e672357e015a000017').each { |notification| notification.update_attributes!(:active => false) }

Or you could do it in one line I guess.

User.find('4ce694e672357e015a000014').notifications.each { |notification| notification.update_attributes!(:active => (notification.id == '4ce694e672357e015a000017' ? true : false)) }

Answer 2

Dave is mostly right, but latest mongoid has a method named update_all and you can use that for setting other notifications to inactive:

User.find('4ce694e672357e015a000014').notifications.excludes(:id => '4ce694e672357e015a000017').update_all(:active => false)