How to break a number into different parts in Java?

Question

I'm looking to do the following : let's say I have a number like 125.625 => I would like to be able to tell my program that is 1 * 100 + 2 * 10 + 5 * 1 + 0.625. How could I do that please ?

thanks

Answer 1

If you have your number as an integer, you could do something like this:

value := 125.625
fractional part := value % 1
value := floor(value)

exponent = 1
listofvaluepairs = array()
while(value > 0)
{
  tmp_part := value % 10
  listofvaluepairs.add(value, exponent)
  exponent = exponent * 10
  value = floor(value / 10)
}

The above psuedocode will fill the listofvaluepairs with pairs of the digit and the number to multiply by. So you'd get this:

{{1,100}, {2,10}, {5,1}}

And the fractional part has that last piece you wanted.

For reference, the floor() function will give the number without the fractional part, so floor(1.6) gives 1. The % (modulo) operator will more or less give the remainder after division. So 7%2 = 1.

What I do in the above example (which is very much not java code), is get one digit at a time from the value.

So I start with 125:

125 % 10 = 5
Then:
floor(125 / 10) = floor(12.5) = 12

Then I repeat to get 2 and 1. At the same time I'm saving 1, 10, and 100 using the exponent variable.

Answer 2

double num = 125.625;
System.out.print(num - (int)num);
num = (int) num;

for (int i=10; num!=0; i*=10) {
    System.out.print(" + " + i/10 + " * " + (num % i)/i*10);
    num -= num % i;
}

Will print:

0.625 + 1 * 5.0 + 10 * 2.0 + 100 * 1.0

Of course you can change the code to add stuff to a data structure.

Answer 3

You can get each digit by using the modulo or % operator in a loop for the integer values (i.e.: int ones = myVal % 10), and to get the fractional value do float fraction = val - (int)val;