How do I access a "Group" member after I run PS "Group-Object"

StackOverflow https://stackoverflow.com/questions/14963267

Question

I have the sourcedata similar to the following denormalized table

DisplayName                  LogRecordCount LogRecordBytes
-----------                  -------------- --------------
Mailbox - Low,                    459          43756
Mailbox - Low,                    1628         185542
Mailbox - Low,                    2575         264474
Mailbox - Low,                     522          48813
Mailbox - Low,                     410         138212
Mailbox - Low,                    1057         200043
Mailbox - Freed                  3866        2170719
Mailbox - Freed                   606         370304
Mailbox - Freed                  4137        1939924
Mailbox - Freed                 3655        1654650

My goal is to write a summary similar to the following

DisplayName                  LogRecordCount  
-----------                  -------------- 
Mailbox - Low,                     6651            
Mailbox - Freed                   12264

The following code is very close to getting what I need, but the "DisplayName" isn't appearing. The value of DisplayName is buried in the result of the Group-Object command.

$stats | ? {$_.DigestCategory -eq 'LogBytes'} | group MailboxGuid | %{
    New-Object psobject -Property @{
        MailboxGuid = $_.Name
        LogRecordBytes = ($_.Group | Measure-Object LogRecordBytes -Sum).Sum
        DisplayName   = $_.Group.DisplayName
    }
}| sort-object LogRecordBytes |  ft -a DisplayName, MailboxGuid, LogRecordBytes

Question

What is the proper syntax for DisplayName = $_.Group.DisplayName to display the display name in the results?

Was it helpful?

Solution

Swap out your DisplayName = .. line with the following:

DisplayName = $_.Group | Select-Object -ExpandProperty DisplayName -Unique

If for some magical reason there are different DisplayName values in the group, you will get an array like {value1, value2}, but normally it will return a single name only :)

OTHER TIPS

Graimer's answer is perfectly fine, but you could also just pluck the DisplayName from the first element of the group, assuming all group elements have the same value for DisplayName

DisplayName = $_.Group[0].DisplayName

Just wanted to let you know of another alternative.

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