How to negate the whole regex?

Question

I have a regex, for example (ma|(t){1}). It matches ma and t and doesn't match bla.

I want to negate the regex, thus it must match bla and not ma and t, by adding something to this regex. I know I can write bla, the actual regex is however more complex.

Answer 1

Use negative lookaround: (?!pattern)

Positive lookarounds can be used to assert that a pattern matches. Negative lookarounds is the opposite: it's used to assert that a pattern DOES NOT match. Some flavor supports assertions; some puts limitations on lookbehind, etc.

Links to regular-expressions.info

• Lookahead and Lookbehind Zero-Width Assertions
• Flavor comparison

See also

• How do I convert CamelCase into human-readable names in Java?
• Regex for all strings not containing a string?
• A regex to match a substring that isn’t followed by a certain other substring.

More examples

These are attempts to come up with regex solutions to toy problems as exercises; they should be educational if you're trying to learn the various ways you can use lookarounds (nesting them, using them to capture, etc):

• codingBat plusOut using regex
• codingBat repeatEnd using regex
• codingbat wordEnds using regex

Answer 2

Assuming you only want to disallow strings that match the regex completely (i.e., mmbla is okay, but mm isn't), this is what you want:

^(?!(?:m{2}|t)$).*$

(?!(?:m{2}|t)$) is a negative lookahead; it says "starting from the current position, the next few characters are not mm or t, followed by the end of the string." The start anchor (^) at the beginning ensures that the lookahead is applied at the beginning of the string. If that succeeds, the .* goes ahead and consumes the string.

FYI, if you're using Java's matches() method, you don't really need the the ^ and the final $, but they don't do any harm. The $ inside the lookahead is required, though.

Answer 3

\b(?=\w)(?!(ma|(t){1}))\b(\w*)

this is for the given regex.
the \b is to find word boundary.
the positive look ahead (?=\w) is here to avoid spaces.
the negative look ahead over the original regex is to prevent matches of it.
and finally the (\w*) is to catch all the words that are left.
the group that will hold the words is group 3.
the simple (?!pattern) will not work as any sub-string will match
the simple ^(?!(?:m{2}|t)$).*$ will not work as it's granularity is full lines