Region: IOError: [Errno 22] invalid mode ('w') or filename

Question

I'm not sure why, but for some reason, whenever I have "region" in the file name of the output file, it gives me this error:

IOError: [Errno 22] invalid mode ('w') or filename: 'path\regionlog.txt'

It does this for "region.txt", "logregion.txt", etc.

class writeTo:
    def __init__(self, stdout, name):
       self.stdout = stdout
       self.log = file(name, 'w') #here is where it says the error occurs

output = os.path.abspath('path\regionlog.txt')
writer = writeTo(sys.stdout, output) #and here too

Why is this? I really would like to name my file "regionlog.txt" but it keeps coming up with that error. Is there a way around it?

Answer 1

Use forward slashes:

'path/regionlog.txt'

Or raw strings:

r'path\regionlog.txt'

Or at least escape your backslashes:

'path\\regionlog.txt'

---

\r is a carriage return.

---

Another option: use os.path.join and you won't have to worry about slashes at all:

output = os.path.abspath(os.path.join('path', 'regionlog.txt'))

Answer 2

In C standard language, \t, \n, \r are escape characters. \t is a transverse to the next TAB position. \n is a newline and \r is a carriage return. You should use \\r or /r, and you will solve the problem!

Answer 3

Additionaly, Python also gives this message when trying to open a file > 50 MB from a SharePoint shared drive.

https://support.microsoft.com/en-us/help/2668751/you-cannot-download-more-than-50-mb-or-upload-large-files-when-the-upl

Answer 4

Another simple solution is changing the "\r" instances in the filename path to "\R"