Zend_Controller_Router_Route_Hostname for two domain names

Question

protected function _initHostnameRouter()
{
    $this->bootstrap('autoload');
    $this->bootstrap('FrontController');

    $front = $this->getResource('FrontController');

    $router = $front->getRouter();

    $hostRoute1 = new Zend_Controller_Router_Route_Hostname('admin.example.net',array('module' => 'admin'));
    $hostRoute2 = new Zend_Controller_Router_Route_Hostname('vouchers.example.net',array('module' => 'vouchers'));
    $pathRoute = new Curo_Route_NoModule();

    $router->removeDefaultRoutes();
    $router->addRoute('default',     $pathRoute);
    $router->addRoute('admin',       $hostRoute1->chain($pathRoute));
    $router->addRoute('vouchers',    $hostRoute2->chain($pathRoute));
}

I have the above code used in Bootstrap file and it is working good. I need to add another domain name for admin module. Now I am using admin.example.net for admin module. I also need to add admin.examplenew.net. I don't need to change the old domain. Both should be working at the same time.

I have tried,

    $hostRoute1 = new Zend_Controller_Router_Route_Hostname('admin.example.net',array('module' => 'admin'));
    $hostRoute2 = new Zend_Controller_Router_Route_Hostname('vouchers.example.net',array('module' => 'vouchers'));
    $hostRoute3 = new Zend_Controller_Router_Route_Hostname('admin.examplenew.net',array('module' => 'adminnew'));
    $pathRoute = new Curo_Route_NoModule();

    $router->removeDefaultRoutes();
    $router->addRoute('default',     $pathRoute);
    $router->addRoute('admin',       $hostRoute1->chain($pathRoute));
    $router->addRoute('vouchers',    $hostRoute2->chain($pathRoute));
    $router->addRoute('adminnew',    $hostRoute3->chain($pathRoute));

But both domain names are not working at the same time.

Answer 1

You are adding $hostRoute1 and $hostRoute3 to the $router under the same name: admin. So the second assignment is overriding the first.

Make the keys unique - by, say, changing the last one to adminnew - and you should be good.