Loop within loop python

Question

I have a log file with several hundred thousand lines.

I am looping through these lines to find any line with some specific text, for example: !!event!!.
Then, once an !!event!! line is found, I need to continue looping after this !!event!! line until I find the next 3 lines which contain their own specific text ('flag1', 'flag2', and 'flag3').
Once I find the third line ('flag3'), I then want to continue looping for the next !!event!! line and repeat the former process until there are no more events.

Does anyone have suggestions on ways I structure my code to accomplish this?

For example:

f = open('samplefile.log','r')
for line in f:
    if '!!event!!' in line:
            L0 = line
        #then get the lines after L0 containing: 'flag1', 'flag2', and 'flag3'
        # below is a sample log file  
        #I am not sure how to accomplish this 
        #(I am thinking a loop within the current loop) 
        #I know the following is incorrect, but the 
         intended result would be able to yield something like this:
            if "flag1" in line:
                L1 = line.split()
            if "flag2" in line:
                L2 = line.split()
            if "flag3" in line:
                L3 = line.split()
print 'Event and flag times: ', L0[0], L1[0], L2[0], L3[0]

samplefile.log

8:41:05 asdfa   32423
8:41:06 dasd    23423
8:41:07 dfsd    342342
8:41:08 !!event!!   23423
8:41:09 asdfs   2342
8:41:10 asdfas  flag1
8:41:11 asda    42342
8:41:12 sdfs    flag2
8:41:13 sdafsd  2342
8:41:14 asda    3443
8:41:15 sdfs    2323
8:41:16 sdafsd  flag3
8:41:17 asda    2342
8:41:18 sdfs    3443
8:41:19 sdafsd  2342
8:41:20 asda    3443
8:41:21 sdfs    4544
8:41:22 !!event!!   5645
8:41:23 sdfs    flag1
8:41:24 sadfs   flag2
8:41:25 dsadf   32423
8:41:26 sdfa    23423
8:41:27 sdfsa   flag3
8:41:28 sadfa   23423
8:41:29 sdfas   2342
8:41:30 dfsdf   2342

the code from this sample should print:

Event and flag times: 8:41:08 8:41:10 8:41:12 8:41:16
Event and flag times: 8:41:22 8:41:23 8:41:24 8:41:27

Answer 1

Sure, you can continue to consume the file in an inner loop, then break out of it when you encounter flag3, and the outer loop will resume:

for line in f:
    if '!!event!!' in line:
        L0 = line.split()
        for line in f:
            if "flag1" in line:
                L1 = line.split()
            elif "flag2" in line:
                L2 = line.split()
            elif "flag3" in line:
                L3 = line.split()
                break             # continue outer loop
        print 'Event and flag times: ', L0[0], L1[0], L2[0], L3[0]

# Event and flag times:  8:41:08 8:41:10 8:41:12 8:41:16
# Event and flag times:  8:41:22 8:41:23 8:41:24 8:41:27

Answer 2

Here you go:

with open("in6.txt") as f:
    flag = False
    c = 0
    d = []
    data = []
    for line in f:
        if flag:
            if "flag1" in line or "flag2" in line:
                data.append(line.split()[0])
            elif "flag3" in line:
                data.append(line.split()[0])
                flag = False
                d.append(data)

            continue
        if "!!event!!" in line:
            flag = True
            data = []
            c = 0
            data.append(line.split()[0])

for l in d:
    print "Event and flag times: ", l[0], l[1], l[2], l[3]

Output

>>> 
Event and flag times:  8:41:08 8:41:10 8:41:12 8:41:16
Event and flag times:  8:41:22 8:41:23 8:41:24 8:41:27

Answer 3

Keep a flag to track what you are looking for:

with open('samplefile.log') as f:
    events = []
    current_event = []
    for line in f:
        if not current_event and '!!event!!' in line:
            current_event.append(line.split()[0])
        else:
            if 'flag1' in line or 'flag2' in line or 'flag3' in line:
                current_event.append(line.split()[0])
                if 'flag3' in line:  # could also be `if len(current_event) == 4:`
                    events.append(current_event)
                    current_event = []

for event in events:
    print 'Event and flag times:', ' '.join(event)

Here I used current_event as the flag; by adding the !!event!! line time to it it becomes non-empty and we start looking for the flags.

I collected the individual event times into a events list, but you could also just print the event data whenever you have found the flag3 line.

Output:

Event and flag times: 8:41:08 8:41:10 8:41:12 8:41:16
Event and flag times: 8:41:22 8:41:23 8:41:24 8:41:27

Answer 4

Just loop over each line, then when you find !!event!!, start looking for the flags, and once all flags are found, continue...

Something like:

def get_time(line):
    return [ i for i in line.split() if i != ''][0]

data = []
index = -1
look_for_flags = False
for line in lines:
    if '!!event!!' in line:
        look_for_flags = True
        data.append([get_time(line)])
        index += 1
    elif look_for_flags:
        if 'flag1' in line or 'flag2' in line or 'flag3' in line:
            data[index].append(get_time(line))
print data

Answer 5

The clearest way to do this is using a generator function, which obviates the need to keep any state. Whenever you need to build a state machine (like you're doing here), think generator.

import sys

def find_target_lines(file_handle):
    target = yield
    for line in file_handle:
        if target in line:
            target = yield line

f = open('samplefile.log','r')
targets = ['!!event!!', 'flag1', 'flag2', 'flag3']

while True:
    found = list()
    finder = find_target_lines(f)
    next(finder)
    try:
        for target in targets:
            line = finder.send(target)
            if line:
                found.append(line)
        print(found)
    except StopIteration:
        break