Splitting a string with curly braces as delimeters?
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05-07-2019 - |
Question
'{5}<blah>{0}</blah>'
i want to turn that into:
['{5}', '<blah>', '{0}', '</blah>']
i currently use: ________.split(/({.*?})/);
but this fails when curly brace is the first character as in the case:
'{0}<blah>'
which gets turned into:
['', '{0}', '<blah>']
... a 3 element array, not a 2
what's wrong with my regex?
Thanks!
Solution
There's nothing wrong with your regex, but there's an issue with how you're using split. Split returns an array based on a delimiter, so if the delimiter is FIRST, it gives you the stuff to the left and right of the split item.
Just check to see if the first item == '' and remove it if it is.
OTHER TIPS
This should do it:
split(/((?!^)\{.*?\})/)
The negative lookahead -- (?!^)
-- succeeds iff the match does not start at the beginning of the string.
What do you think of:
'{5}<blah>{0}</blah>'.split(/{([^}]+)}/g)
The value of the curly blocks are every 2 items from the item 1.