Pierre, I thought a better solution could be the following (inspiration from this gist):
a = A.arel_table
b = B.arel_table
subquery = b.project(b[:a_id].as('A_id')).where{c > 4}
subquery = subquery.as('intm_table')
query = A.join(subquery).on(subquery[:A_id].eq(a[:id]))
No particular reason for naming the alias as "intm_table", I just thought it would be less confusing.