Question

I have a problem using a shared_ptr of a base class, I can't seem to be able to call the derived class's methods when dereferencing it. I believe code will be more verbose than me:

class Base : public boost::enable_shared_from_this<Base>
{
  public:
    typedef  boost::shared_ptr<BabelNet> pointer;
};

class Derived : public Base
{
  public:
     static pointer  create()
                {
                        return pointer(new Derived);
                }
     void             anyMethod()
     {
        Base::pointer foo = Derived::create();
        // I can't call any method of Derived with foo
        // How can I manage to do this ?
        // is dynamic_cast a valid answer ?
        foo->derivedMethod(); // -> compilation fail
     }

};
Was it helpful?

Solution

see static_cast with boost::shared_ptr?

you'll need to use dynamic_pointer_cast to get the appropriate shared_ptr instantiation. (corresponding to a dynamic_cast)

OTHER TIPS

Shared pointer or not, when you have a pointer to a Base, you can only call member functions from Base.

If you really need to dynamic_cast, you can use dynamic_pointer_cast from boost, but chances are that you shouldn't. Instead, think about your design : Derived is a Base, and this is an extremely strong relationship, so think carefully about Base interface and if the concrete type really has to be known.

If derivedMethod is not declared in base class (virtual or not), then it is normal that the compilation would fail. The shared ptr knows and uses the base class (through the pointer it holds), and knows nothing about the derived class and its specific methods.

Your code wouldn't work even with raw pointers.

You need either to declare derivedMethod() method even in base class or to have a pointer to aDerived object.

Licensed under: CC-BY-SA with attribution
Not affiliated with StackOverflow
scroll top