You need to invoke recognizer in a loop:
Result result;
while(true) {
result = recognizer.recognize();
if (result == null)
break;
}
Question
I am new to Sphinx 4 and trying to make simple digits recognition application. I have set of wavs with 3 digits pronounced with short pause (like one_five_nine.wav) for test. The problem is that recognition of file stops after first digit found, so I have only "one" as output for one_five_nine.wav.
Here is my front-end config
<component name="epFrontEnd16k" type="edu.cmu.sphinx.frontend.FrontEnd">
<propertylist name="pipeline">
<item>audioFileDataSource</item>
<item>dataBlocker </item>
<item>speechClassifier </item>
<item>speechMarker </item>
<item>nonSpeechDataFilter </item>
<item>preemphasizer </item>
<item>windower </item>
<item>fft </item>
<item>melFilterBankFor16k</item>
<item>dct </item>
<item>liveCMN </item>
<item>featureExtraction </item>
</propertylist>
</component>
and code
Recognizer recognizer = (Recognizer) cm.lookup("recognizer");
recognizer.allocate();
AudioFileDataSource dataSource = (AudioFileDataSource) cm.lookup("audioFileDataSource");
File folder = new File(testDataSetDirectory);
for (final File fileEntry : folder.listFiles()) {
// retrive URL
URL audioURL = null;
try {
audioURL = fileEntry.toURL();
} catch (MalformedURLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
// configure the audio input for the recognizer
dataSource.setAudioFile(audioURL, null);
Result result = recognizer.recognize();
String recognizedText = result != null ? result.getBestFinalResultNoFiller() : "null";
// print
System.out.println(fileEntry.getName() + ":\t" + recognizedText);
}
Thank you for help.
Solution
You need to invoke recognizer in a loop:
Result result;
while(true) {
result = recognizer.recognize();
if (result == null)
break;
}