Question

public class Test {

    Integer i;
    int j;

    public static void main ( String [] args ) {
       Test t = new Test ();
       t.go();
    }

    public void go() {
       j=i;
       System.out.println(j);
       System.out.println(i);
    }
}

Output : Exception in thread "main" java.lang.NullPointerException at Test.go(Test.java:12) at Test.main(Test.java:8)

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Solution

That's obviously not the error. You will get a runtime NullPointerException because you're unboxing a null reference (i) into a primitive (j). See JLS §5.1.8.

The reason i is null is that instance fields are initialized to 0, null, or false by default.

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