Question

I'm new to Qt, so I wonder whether there is a way to set the size of a QMainWindow to (for example) 70% of the user's desktop.
I tried the stretch factor but it didn't work. QWidget::setFixedSize worked but only with a pixel number, I think.

Was it helpful?

Solution 2

Thanks to Amir eas. The problem is solved. Here's the code for it:

#include <QDesktopWidget>
#include <QMainWindow>
...
QDesktopWidget dw;
MainWindow w;
...
int x=dw.width()*0.7;
int y=dw.height()*0.7;
w.setFixedSize(x,y);

OTHER TIPS

Somewhere in your QMainWindow constructor, do this:

resize(QDesktopWidget().availableGeometry(this).size() * 0.7);

This will resize the window to 70% of the available screen space.

You can use the availableGeometry(QWidget*) method in QDesktopWidget, this will give you the geometry of the screen that this widget is currently on.
For example:

QRect screenSize = desktop.availableGeometry(this);
this->setFixedSize(QSize(screenSize.width * 0.7f, screenSize.height * 0.7f));

Where this is the MainWindow pointer. This will work when using multiple screens.

Just to update @muesli's answer for Qt6, QDesktopWidget had been deprecated in Qt5 and in Qt6 is removed.

The new equivalent code is

resize(QGuiApplication::primaryScreen()->availableGeometry().size() * 0.7);
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