You can't in a single #ifdef
would a single #if
do instead?
#if defined(__APPLE__) || defined(__linux)
this also works if you prefer
#if defined __APPLE__ || defined __linux
Question
I have some C++ code, and want to perform an action if the __APPLE__
or __linux
macros are defined.
If I did it as a normal if
conditional, it would be easy using ||
:
if (something || something) { .. code .. }
But as of what I know there is no ||
operator for #ifdef
statements. How would I check if __APPLE__
or __linux
is defined using a single #ifdef
statement?
Solution
You can't in a single #ifdef
would a single #if
do instead?
#if defined(__APPLE__) || defined(__linux)
this also works if you prefer
#if defined __APPLE__ || defined __linux
OTHER TIPS
In my C++ there is.
#if defined(__APPLE__) || defined(__linux)
// ...
#endif