Question

This is what I have, currently. Is there any nicer way to do this?

import struct
def int32_to_uint32(i):
    return struct.unpack_from("I", struct.pack("i", i))[0]
Was it helpful?

Solution

Not sure if it's "nicer" or not...

import ctypes

def int32_to_uint32(i):
    return ctypes.c_uint32(i).value

OTHER TIPS

using numpy for example:

import numpy
result = numpy.uint32( numpy.int32(myval) )

or even on arrays,

arr = numpy.array(range(10))
result = numpy.uint32( numpy.int32(arr) )

I just started learning python, but something simple like this works for values in the range of a signed 32-bit integer

def uint(x):
  if x < 0:
    return hex(0xffff_ffff - abs(x) + 1)
  else:
    return hex(x)
Licensed under: CC-BY-SA with attribution
Not affiliated with StackOverflow
scroll top