Need the path for particular files using os.walk()

Question

I'm trying to perform some geoprocessing. My task is to locate all shapefiles within a directory, and then find the full path name for that shapefile within the directory. I can get the name of the shapefile, but I don't know how to get the full path name for that shapefile.

shpfiles = []
for path, subdirs, files in os.walk(path):
    for x in files:
        if x.endswith(".shp") == True:
            shpfiles.append[x]

Answer 1

os.walk gives you the path to the directory as the first value in the loop, just use os.path.join() to create full filename:

shpfiles = []
for dirpath, subdirs, files in os.walk(path):
    for x in files:
        if x.endswith(".shp"):
            shpfiles.append(os.path.join(dirpath, x))

I renamed path in the loop to dirpath to not conflict with the path variable you already were passing to os.walk().

Note that you do not need to test if the result of .endswith() == True; if already does that for you, the == True part is entirely redundant.

You can use .extend() and a generator expression to make the above code a little more compact:

shpfiles = []
for dirpath, subdirs, files in os.walk(path):
    shpfiles.extend(os.path.join(dirpath, x) for x in files if x.endswith(".shp"))

or even as one list comprehension:

shpfiles = [os.path.join(d, x)
            for d, dirs, files in os.walk(path)
            for x in files if x.endswith(".shp")]

Answer 2

Why not import glob ?

import glob 

print(glob.glob('F:\OTHERS\PHOTOS\Panama\\mai13*\\*.jpg') )

and i get all the jpeg i want, with absolute path

>>> 
['F:\\OTHERS\\PHOTOS\\Panama\\mai13\\03052013271.jpg', 
'F:\\OTHERS\\PHOTOS\\Panama\\mai13\\05052013272.jpg', 
'F:\\OTHERS\\PHOTOS\\Panama\\mai13\\05052013273.jpg']

Answer 3

Seems os.path.abspath(finename) will work. Please try.

shpfiles = []
for path, subdirs, files in os.walk(path):
    for x in files:
        if x.endswith(".shp") == True:
            shpfiles.append(os.path.join(path, x))