You are running into a problem related to Java generics. To summarize, when deserializing data into a non-reifiable type (aka a type for which actual type information is not available at runtime) you need to use a supertype token. You can get more detail about what a supertype token is (and why you need to use one) by reading these SO posts:
- Pass parameterized type to method as argument
- Error using Jackson and JSON
- Deserialize JSON to ArrayList using Jackson
And also from the Jackson documentation:
The basic problem is that when you use a typical generic object, the actual type parameters for the object aren't available at runtime. Therefore Jackson doesn't know which actual class to instantiate and deserialize your data into.
The easiest way to get around the problem would be adding an overload to your JSON utility class, that accepts a type reference (as opposed to a Class<T>
). For example:
public static <T> T fromJson(String json, TypeReference<T> typeRef) {
if(json == null || typeRef == null) return null;
return new ObjectMapper().readValue(json, typeRef);
}
To be used as such:
Map<String, SomeClass> actual = JsonUtil.fromJson(
encoded,
new TypeReference<Map<String, SomeClass>>(){});