Question

The following fails:

$result = mysql_query("SELECT * FROM Tasks WHERE UserID = '$_SESSION['userID']'");

I tried the following:

$userID = $_SESSION['userID'];
$result = mysql_query("SELECT * FROM Tasks WHERE UserID = '$userID'");

and it works. Is there a way to do this without making a separate variable?

Thanks!

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Solution

Or like this:

$result = mysql_query("SELECT * FROM Tasks WHERE UserID = '{$_SESSION['userID']}'");

OTHER TIPS

$result = mysql_query("SELECT * FROM Tasks WHERE UserID = '".$_SESSION['userID']."'");

or

$result = mysql_query("SELECT * FROM Tasks WHERE UserID = '{$_SESSION['userID']}'");

worth noting it would recommend the first one because it gets easier to read/find when you use a php editor, which in return makes it easier to debugg

Your first chokes the query, because you're actually commanding WHERE userID is '$_SESSION['. Not to mentions that rest which is userID']}' will be interpreted as a syntax error by MySQL.

Yes, like this

$result = mysql_query("SELECT * FROM Tasks WHERE UserID = '$_SESSION[userID]'");
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