How to list all different properties in DBPedia

Question

I have a burning question concerning DBpedia. Namely, I was wondering how I could search for all the properties in DBpedia per page. The URI http://nl.dbpedia.org/property/einde concerns the property "einde". I would like to get all existing property/ pages. This does not seem too hard, but I don't know anything about SPARQL, so that's why I want to ask for some help. Perhaps there is some kind of dump of it, but I honestly don't know.

Answer 1

I second Joshua Taylor's answer, however if you want to limit the properties to the Dutch DBpedia, you need to change the default-graph-uri query parameter to nl.dbpedia.org and set the SPARQL endpoint to nl.dbpedia.org/sparql, as in the following query. You will get a result-set of just above 8000 elements.

SELECT DISTINCT ?pred WHERE {
  ?pred a rdf:Property
}
ORDER BY ?pred

run query

These are the Dutch translations of the properties that have been mapped from Wikipedia so far. The full English list is also available. According to mappings.dbpedia.org, there are ~1700 properties with missing Dutch translations.

Answer 2

Rather than asking for pages whose URLs begin with, e.g., http://nl.dbpedia.org/property/, we can express the query by asking “for which values of ?x is there a triple ?x rdf:type rdf:Property in DBpedia?” This is a pretty simple SPARQL query to write. Because I expected that there would be lots of properties in DBPedia, I first wrote a query to count how many there are, and afterward wrote a query to actually list them.

There are 48292 things in DBpedia declared to be of rdf:type rdf:Property, as reported by this SPARQL query, run against one of DBpedia's SPARQL endpoints:

select COUNT( ?property ) where {
 ?property a rdf:Property
}

SPARQL Results

You can get the list by selecting ?property instead of COUNT( ?property ):

select ?property where {
 ?property a rdf:Property
}

SPARQL Results