Python: wrapping method invocations with pre and post methods
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06-07-2019 - |
Question
I am instantiating a class A (which I am importing from somebody else, so I can't modify it) into my class X.
Is there a way I can intercept or wrap calls to methods in A? I.e., in the code below can I call
x.a.p1()
and get the output
X.pre
A.p1
X.post
Many TIA!
class A:
# in my real application, this is an imported class
# that I cannot modify
def p1(self): print 'A.p1'
class X:
def __init__(self):
self.a=A()
def pre(self): print 'X.pre'
def post(self): print 'X.post'
x=X()
x.a.p1()
Solution
Here is the solution I and my colleagues came up with:
from types import MethodType
class PrePostCaller:
def __init__(self, other):
self.other = other
def pre(self): print 'pre'
def post(self): print 'post'
def __getattr__(self, name):
if hasattr(self.other, name):
func = getattr(self.other, name)
return lambda *args, **kwargs: self._wrap(func, args, kwargs)
raise AttributeError(name)
def _wrap(self, func, args, kwargs):
self.pre()
if type(func) == MethodType:
result = func( *args, **kwargs)
else:
result = func(self.other, *args, **kwargs)
self.post()
return result
#Examples of use
class Foo:
def stuff(self):
print 'stuff'
a = PrePostCaller(Foo())
a.stuff()
a = PrePostCaller([1,2,3])
print a.count()
Gives:
pre
stuff
post
pre
post
0
So when creating an instance of your object, wrap it with the PrePostCaller object. After that you continue using the object as if it was an instance of the wrapped object. With this solution you can do the wrapping on a per instance basis.
OTHER TIPS
The no-whistles-or-bells solution would be to write a wrapper class for class A that does just that.
You could just modify the A instance and replace the p1 function with a wrapper function:
def wrapped(pre, post, f):
def wrapper(*args, **kwargs):
pre()
retval = f(*args, **kwargs)
post()
return retval
return wrapper
class Y:
def __init__(self):
self.a=A()
self.a.p1 = wrapped(self.pre, self.post, self.a.p1)
def pre(self): print 'X.pre'
def post(self): print 'X.post'
As others have mentioned, the wrapper/decorator solution is probably be the easiest one. I don't recommend modifyng the wrapped class itself, for the same reasons that you point out.
If you have many external classes you can write a code generator to generate the wrapper classes for you. Since you are doing this in Python you can probably even implement the generator as a part of the program, generating the wrappers at startup, or something.
I've just recently read about decorators in python, I'm not understanding them yet but it seems to me that they can be a solution to your problem. see Bruce Eckel intro to decorators at: http://www.artima.com/weblogs/viewpost.jsp?thread=240808
He has a few more posts on that topic there.
Edit: Three days later I stumble upon this article, which shows how to do a similar task without decorators, what's the problems with it and then introduces decorators and develop a quite full solution: http://wordaligned.org/articles/echo
Here's what I've received from Steven D'Aprano on comp.lang.python.
# Define two decorator factories.
def precall(pre):
def decorator(f):
def newf(*args, **kwargs):
pre()
return f(*args, **kwargs)
return newf
return decorator
def postcall(post):
def decorator(f):
def newf(*args, **kwargs):
x = f(*args, **kwargs)
post()
return x
return newf
return decorator
Now you can monkey patch class A if you want. It's probably not a great idea to do this in production code, as it will effect class A everywhere. [this is ok for my application, as it is basically a protocol converter and there's exactly one instance of each class being processed.]
class A:
# in my real application, this is an imported class
# that I cannot modify
def p1(self): print 'A.p1'
class X:
def __init__(self):
self.a=A()
A.p1 = precall(self.pre)(postcall(self.post)(A.p1))
def pre(self): print 'X.pre'
def post(self): print 'X.post'
x=X()
x.a.p1()
Gives the desired result.
X.pre
A.p1
X.post