wxProgressDialog like behaviour for a wxDialog

Question

I want to create modal dialog but which shouldn't behave in a modal way i.e. control flow should continue

if i do

 dlg = wx.Dialog(parent)
 dlg.ShowModal()

 print "xxx"

 dlg.Destroy()

"xxx" will not get printed, but in case of progress dialog

dlg = wx.ProgressDialog.__init__(self,title, title, parent=parent, style=wx.PD_APP_MODAL)
print "xxx"

dlg.Destroy()

"xxx" will get printed

so basically i want to achieve wx.PD__APP__MODAL for a normal dialog?

Answer 1

It was very trivial, just using wx.PD_APP_MODAL style in wx.Dialog allows it to be modal without stopping the program flow, only user input to app is blocked, i thought PD_APP_MODAL is only for progress dialog

Answer 2

Just use Show instead of ShowModal.

If your function (the print "xxx" part) runs for a long time you will either have to manually call wx.SafeYield every so often or move your work to a separate thread and send custom events to your dialog from it.

One more tip. As I understand, you want to execute some code after the modal dialog is shown, here is a little trick for a special bind to EVT_INIT_DIALOG that accomplishes just that.

import wx

class TestFrame(wx.Frame):
    def __init__(self):
        wx.Frame.__init__(self, None)
        btn = wx.Button(self, label="Show Dialog")
        btn.Bind(wx.EVT_BUTTON, self.ShowDialog)

    def ShowDialog(self, event):
        dlg = wx.Dialog(self)
        dlg.Bind(wx.EVT_INIT_DIALOG, lambda e: wx.CallAfter(self.OnModal, e))
        dlg.ShowModal()
        dlg.Destroy()

    def OnModal(self, event):
        wx.MessageBox("Executed after ShowModal")

app = wx.PySimpleApp()
app.TopWindow = TestFrame()
app.TopWindow.Show()
app.MainLoop()