IF/ELSEIF comparing variables from database

Question

Hello I'm new to PHP.

So I have this query here that checks if Order Total's status is set to 1 or 0 in the database

$chk_dscnt=mysql_query("SELECT * FROM `discount` WHERE `discount_type` = 'Order Total'  ");
while ($x=mysql_fetch_array($chk_dscnt)) {
    echo $x['status'];
}

(I already have a function to change the status to 1 or 0).

I would like to do a discount on the $grand_total if the status is 1 and display the normal $grand_total if the status is 0. But even if I set the status to 1 or 0 it always performs the elseif statement and displays the undiscounted price or the normal price.

Is there any logical or syntax error ?? need you help guys :)

if ($x == '1') 
{   
    $subt = 0;
        $discounted_price= $grand_total - ($grand_total*(5/100) );
        $subt= $subt + $discounted_price;
        echo '<input type=text name=total value='.$subt.'>';
}
else if($x == '0'){ 

     $subt =$grand_total; ;
        echo '<input type=text name=total value='.$subt.'>';

}

Answer 1

in your case $x is an array. so you can't compare array to a string like this

if ($x == '1')

you need to use the index to compare

if ($x['status'] == '1')